First slide

Standing waves

Question

Air is blown at the mouth of a tube (length 25 cm and diameter 3 cm) closed at one end. Velocity of sound is 330 m,/s. The sound which is produced will
correspond to the frequencies

Moderate

A

330 Hz
B

combination of frequencies 390, 660, Sg0, 1320,1650 Hz
C

combination of frequencies 330, 99O, 1650, 2370 Hz
D

combination of frequencies 300, 900, 1500, 2L00 Hz

Solution

In case of closed pipe
$n_{1} = \frac{V}{4 l} = \frac{330}{4 Ã 0 â 25} = 330 Hz n_{2} = \frac{3 V}{4 l} = \frac{3 Ã 330}{4 Ã 0 â 25} = 990 Hz n_{3} = 5 n_{1} = 1650 Hz n_{4} = 7 n_{1} = 2310 Hz$

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