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An air capacitor of capacity C=10μF  is connected to a constant voltage battery of 12V . Now the space between the plates is filled with a liquid of dielectric constant 5. The charge that flows now from battery to the capacitor is

a
120μC
b
699μC
c
480μC
d
24μC

detailed solution

Correct option is C

Initially charge on the capacitor  Qi=CoV=10×12=120μCFinally charge on the capacitor  Qf=CV=KCoV=5×10×12=600μCSo charge supplied by the battery later =Qf−Qi=480μC.

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