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Q.

An air capacitor of capacity C=10μF  is connected to a constant voltage battery of 12 V . Now the space between the plates is filled with a liquid of dielectric constant 5. The charge that flows now from battery to the capacitor is

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a

120μC

b

699μC

c

480μC

d

24μC

answer is C.

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Detailed Solution

Initially charge on the capacitor  Qi=CoV=10×12=120μCFinally charge on the capacitor  Qf=CV=KCoV=5×10×12=600μCSo charge supplied by the battery later =Qf−Qi=480μC.
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