An air capacitor of capacity C=10μF is connected to a constant voltage battery of 12 V. Now the space between the plates is filled with a liquid of dielectric constant 5. The charge that flows now from battery to the capacitor is
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a
120 μC
b
699 μC
c
480 μC
d
24 μC
answer is C.
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Detailed Solution
Initially charge on the capacitor Q=10×12=120 μCFinally charge on the capacitor Q'=(5×10)×12=600 μCSo charge supplied by the battery later =Q'−Q=480 μC