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Q.

An air capacitor of capacity C=10μF is connected to a constant voltage battery of 12 V. Now the space between the plates is filled with a liquid of dielectric constant 5. The charge that flows now from battery to the capacitor is

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a

120 μC

b

699 μC

c

480 μC

d

24 μC

answer is C.

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Detailed Solution

Initially charge on the capacitor Q=10×12=120 μCFinally charge on the capacitor Q'=(5×10)×12=600 μCSo charge supplied by the battery later =Q'−Q=480 μC
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