An air capacitor consists of two identical parallel plates A and B as shown in figure. Plate A is given change Q and plate B is given a charge 3Q . P is the median plane of the capacitor. If C0 is the capacitance of the capacitor then

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VP−VA=Q4Co

VP−VA=Q2Co

VP−VA=−QCo

VP−VB=−Q4Co

answer is B.

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Detailed Solution

The distribution of charges on plates areE at any point between the plates is E=σ2∈0+σ2∈0=σ∈=QA∈odv=−E.dr⇒VA−VP=−QA∈o×d2∴VP−VA=Q2Co

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