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In an Air conditioner compartment of a train if a material of thermal conductivity K and thickness 10 cm is required to fulfill the purpose. To do so there is a need of two glass each of thickness 1 cm with air gap of 8 cm between them. If thermal conductivity of glass and air are 1 W/mK and 0.01 W/mK then the value of K is:

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0.0125W / mK

0.05W / mK

0.255W / mK

0.33W / mK

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detailed solution

Correct option is A

Thermal Resistance, Rth=LKALKA=L1K1A+L2K2A⇒10KA=1(1)A+80.01A⇒K=10800+1⇒K=0.0125

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