Air is filled at 600C in a vessel of open mouth. The vessel is heated to a temperature ‘T’ so that 1/4th mass of air escapes from the vessel. Assuming the volume of vessel remaining constant, the value of ‘T’ is
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a
800C
b
4440C
c
3330C
d
1710C
answer is D.
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Detailed Solution
PV=mMRT⟹T∝1MT1=607−273=333KT1T2=m2m1333T2=m34mT2=444K Value of T2 is 444Kelvin or 171∘C