An AIR station is broadcasting the waves of wavelength 300 metres. If the radiating power of the transmitter is 10 kW then the number of photons radiated per second is

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1.5×1029

1.5×1031

1.5×1033

1.5×1035

answer is B.

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Detailed Solution

P=Wt=nhcλt⇒nt=Pλhc=10×103×3006.6×10−34×3×108=1.5×1031

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