First slide

Quantum Theory of Light

Question

An AIR station is broadcasting the waves of wavelength 300 metres. If the radiating power of the transmitter is 10 kW then the number of photons radiated per second is

Easy

A

$1 .5 \times 10^{29}$
B

$1 .5 \times 10^{31}$
C

$1 .5 \times 10^{33}$
D

$1 .5 \times 10^{35}$

Solution

$P = \frac{W}{t} = \frac{nhc}{λt} \Rightarrow (\frac{n}{t}) = \frac{Pλ}{hc} = \frac{10 \times 10^{3} \times 300}{6 .6 \times 10^{- 34} \times 3 \times 10^{8}} = 1 .5 \times 10^{31}$

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