First slide

Projection Under uniform Acceleration

Question

An airplane moving horizontally with a speed of 180 km/hr drops a food packet while flying at a height of 500 m. The horizontal range is:

Moderate

A

180 m
B

980 m
C

500 m
D

670 m

Solution

$s = ut + \frac{1}{2} {gt}^{2}$
$500 = \frac{1}{2} \times 10 \times t^{2} or t = 10 \sec .$
Horizontal range x = $\frac{180 \times 5}{18} \times 10 = 500 m$

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