Al object is placed at a distance of f/2 from a convex lens. The image will be

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At one of the foci, virtual and double its size

At 3 f/2, real and inverted

At 2 f, virtual and erect

None of these

answer is A.

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Detailed Solution

1f=1v+1uGiven u=−f2⇒1f=1v+1f/2⇒1v=1f−1f⇒1v=−1f and m=vu=ff/2=2So virtual at the focus and of double size.

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