All the particles thrown with same initial velocity would strike the ground.

(KE+PE)f=(KE+PE)i in all situations. Hence, KEf is also equal as PEf=0. Hence, all the particles collide with the same speed.−h=vt1−12gt12  [for first particle]  ……..(i)−h=−vt2−12gt22   [for second particle]  ……..(ii)From Eq. (i) and Eq. (ii), t2 > t1 t2 = maximum, t1 = minimum i.e., options (3) and (4) are correct.