All the particles thrown with same initial velocity would strike the ground.

(KE+PE)f=(KE+PE)i in all solutions.Hence, KEf is also equal as PEf=0. Hence, all the particles collide with the same speed. −h=vt1−12gt12 [for first particle]  ………(i)−h=−vt2−12gt22  [for the second particle] ………(ii)From Eq. (i) and Eq. (ii),t2>t1t2= maximum, t1=minimum i.e., options (c) and (d) are correct.