First slide

Electrostatic potential

Question

An alpha particle is accelerated through a potential difference of $10^{6} volt$ . Its kinetic energy will be

Easy

A

$1 MeV$
B

$2 MeV$
C

$4 MeV$
D

$8 MeV$

Solution

$K = qV = 2 e \times 10^{6} J = \frac{2 e \times 10^{6}}{e} eV = 2 MeV$

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