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An alpha particle is accelerated through a potential difference of $10^{6} volt$ . Its kinetic energy will be

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detailed solution

Correct option is B

K=qV=2e×106J=2e×106eeV=2MeV

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An alpha particle is accelerated through a potential difference of 106 volt. Its kinetic energy will be

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An alpha particle is accelerated through a potential difference of $10^{6} volt$ . Its kinetic energy will be