First slide

Potential energy

Question

An alpha particle is accelerated through a potential difference of 10⁶ volts. Its kinetic energy will be

Easy

A

1 MeV
B

2 MeV
C

4 MeV
D

8 MeV

Solution

$K = qV = 2 e \times 10^{6} J = \frac{2 e \times 10^{6}}{e} eV = 2 MeV$

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