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An alpha particle of energy 5 MeV is scattered through 180° by a fixed uranium nucleus. The distance of the closest approach is of the order of
detailed solution
Correct option is C
Use E=14πε0(Ze)(e)r0 5×1.6×10-13=9×109×2×92×1.6×10-192r0 r0=5.3×10-14m≈10-12cmTalk to our academic expert!
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A beam of fast moving alpha particles were directed towards a thin film of gold. The parts and of the transmitted and reflected beams corresponding to the incident parts A, B and C of the beam, are shown in the adjoining diagram. The number of alpha particles in
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