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CIrcuit questions

Question

An alternating current having peak value 28 A is used to heat a metal wire. To produce the same heating effect, a constant current i can be used where i is

Easy

Solution

$i_{d c} = i_{r m s} = \frac{i_{p e a k}}{\sqrt{2}} = \frac{28}{\sqrt{2}} = 20 A (a p p r o x)$

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