An alternating e.m.f. of angular frequency ω is applied across an inductance. The instantaneous power developed in the circuit has an angular frequency
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a
ω4
b
ω2
c
ω
d
2 ω
answer is D.
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Detailed Solution
The instantaneous values of emf and current in inductive circuit are given by E=E0sinωt and i=i0sinωt−π2 respectively. So, Pinst =Ei=E0sinωt×i0sinωt−π2 =E0i0sinωtsinωtcosπ2−cosωtsinπ2=E0i0sinωtcosωt=12E0i0sin2ωt (sin2ωt=2sinωcosωt)Hence, angular frequency of instantaneous power is 2 ω