An alternating emf of e=200sin 100πt is applied across a capacitor of capacitance 10.628μF , the capacitive reactance and the peak current is

see full answer

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!

An Intiative by Sri Chaitanya

2000πΩ,4×10−2πA

2000Ω, 10−1A

200Ω, 20A

2000Ω, 5×10−3A

answer is B.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

XC=1ωC=1100π×10.628×10−6=106×0.620100×3.14=2000Ω io=εoXC=2002000=10−1 .

Watch 3-min video & get full concept clarity