An alternating voltage is connected in series with a resistance R and an inductance L If the potential drop across the resistance is 200 V and across the inductance is 150 V, then the applied voltage is

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350 V

250 V

500 V

300 V

answer is B.

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Detailed Solution

The applied voltage is given by V=VR2+VL2 V=(200)2+(150)2=250 volt

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