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Q.

An alternating voltage v=100cos⁡100πt volt is applied across a 100μF capacitor. Then average electrostatic energy stored in it is

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a

zero

b

1.5 J

c

0.5 J

d

0.25 J

answer is D.

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Detailed Solution

QC=V⇒Q100×10−6=100cos⁡100πt⇒Q=10−2cos⁡100πt  coulomb∴ Qrms=10−22 coulomb∴ U=Qrms2/2C=(10−22)2×12×10−4J=0.25 J
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