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Questions  

An alternating voltage v=100cos100πt volt is applied across a 100μF capacitor. Then average electrostatic energy stored in it is 

a
zero
b
1.5 J
c
0.5 J
d
0.25 J

detailed solution

Correct option is D

QC=V⇒Q100×10−6=100cos⁡100πt⇒Q=10−2cos⁡100πt  coulomb∴ Qrms=10−22 coulomb∴ U=Qrms2/2C=(10−22)2×12×10−4J=0.25 J

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