First slide

Phasors and Phasor Diagrams

Question

An alternating voltage v = 300 $\sqrt{2} \sin (60 t)$ (in volts) is connected across a 4 $μ$ F capacitor through an a.c. ammeter. The reading of ammeter will be

Easy

A

$40 \sqrt{2} m A$
B

$30 \sqrt{2} m A$
C

72 mA
D

40 mA

Solution

$V_{0} = 300 \sqrt{2} ∴ V_{r m s} = \frac{V_{0}}{\sqrt{2}} = 300 V o l t$
$I = \frac{V_{r m s}}{X_{C}} = v_{r m s} \times ω c = 300 \times 60 \times 4 \times 10^{- 6}$
$I = 72 \times 10^{- 3} A; I = 72 m A$

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