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Q.

An alternating voltage v = 300 2 sin (60t)  (in volts) is connected across a 4 μF capacitor through an a.c. ammeter. The  reading of ammeter will be

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a

402 mA

b

302 mA

c

72 mA

d

40 mA

answer is C.

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Detailed Solution

V0=3002     ∴     Vrms=V02=300 VoltI=VrmsXC=vrms×ωc=300×60×4×10−6I=72×10−3A;I=72 mA
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