An aluminium rod has a breaking strain $0.2\%$ .  The minimum cross-sectional area of the rod in $m^2$ in order to support a load of ${10}^{4}N$  is, if Young's modulus is $7\times {10}^{9}N{m}^{-2}$ , 

• A

  $1.7\times {10}^{-4}$

• B

  $1.7\times {10}^{-3}$

• C

  $7.1\times {10}^{-4}$

• D

  $1.4\times {10}^{-4}$