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Q.

An aluminium and steel wires of same length and cross-section are attached end to end. The compound wire is hung from a rigid support and a load is suspended from the free end. Y of steel is ( 20/7) times of aluminium. The ratio of increase of length of steel wire to aluminium wire is:

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a

20 : 3

b

10 : 7

c

7 : 20

d

1 : 7

answer is C.

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Detailed Solution

∆l=FLAY⇒∆l∞1y⇒(∆l)steel(∆l)Al=YAlYsteel=720
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