Q.
An aluminum wire and a copper wire of the same length and cross section are joined end to end. The composite wire is hung from a rigid support and a load is suspended from the free end. if the increase in length of the composite wire is 1.8mm, find the increase in the length of each wire. (YAl=7×1010Nm–2, YCu=1.1×1011Nm–2)
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a
1.1 mm, 0.7 mm
b
0.7 mm, 1.1 mm
c
2.2 mm, 1.4 mm
d
1.4 mm, 2.2 mm
answer is A.
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Detailed Solution
e∝1Y∵Y=FlAee1e2=Y2Y1⇒e11.8-e1=1.1×10117×1010⇒e1=1.1⇒e2=1.8-1.1=0.7
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