Q.

An aluminum wire and a copper wire of the same length and cross section are joined end to end. The composite wire is hung from a rigid support and a load is suspended from the free end. if the increase in length of the composite wire is 1.8mm, find the increase in the length of each wire. (YAl=7×1010Nm–2, YCu=1.1×1011Nm–2)

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a

1.1 mm,  0.7 mm

b

0.7 mm,  1.1 mm

c

2.2 mm,  1.4 mm

d

1.4 mm,  2.2 mm

answer is A.

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Detailed Solution

e∝1Y∵Y=FlAee1e2=Y2Y1⇒e11.8-e1=1.1×10117×1010⇒e1=1.1⇒e2=1.8-1.1=0.7
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