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An AM wave is expressed as E=10(1+0.6Cos2000πt)Cos2×108πt  Volts , the minimum and maximum values of modulated carrier wave are

a
10 V , 20 V
b
4 V , 8V
c
4 V , 16 V
d
8 V , 20 V

detailed solution

Correct option is C

Modulated signal can be written as E(t)=Ec1+μ coswmtcoswct Given equation E=101+0.6 cos2000πtcos2×108πt Comparing equations   μ = 0.6    and    Ec=10  Now, Emax=(1+μ)Ec = (1+0.6)10 = 16 V and    Emin=(1−μ)Ec  = (1−0.6)10 = 4 V

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