Q.

In an AM wave , maximum voltage was found to be 16 V and minimum voltage was found to be 4 V, the percentage of modulation is

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a

40 %

b

25 %

c

33 %

d

60 %

answer is D.

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Detailed Solution

Ma=Emax−EminEmax+Emin×100=16−416+4×100 = 60%
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