Questions
In an AM wave , maximum voltage was found to be 16 V and minimum voltage was found to be 4 V, the percentage of modulation is
detailed solution
Correct option is D
Ma=Emax−EminEmax+Emin×100=16−416+4×100 = 60%Talk to our academic expert!
Similar Questions
A message signal of frequency 10 kHz and peak voltage of 10 volts is used to modulate a carrier of frequency 1 MHz and peak voltage of 20 volts. The side bands are 1010 kHz and______________kHz.
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