Questions

An ammeter is obtained by shunting a 30 $Ω$ galvanometer with a 30 $Ω$ resistance. What additional shunt should be connected across it to double the range ?

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15 Ω

10 Ω

5 Ω

None of the above

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detailed solution

Correct option is A

For ammeterS=igi−ig×G∴ SG=igi−ig or GS=iig−1or 3030=iig−1 or i=2igNew range is doubled i.e., 4igNow shunt requiredS=ig4ig−ig30=10ΩThis can be obtained by shunting the earlier shunt of 30 Ωith a new shunt of 15Ω

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