First slide

Young's double slit Experiment

Question

Among the two interfering monochromatic sources A and B; A is ahead of B in phase by 66⁰. If the observation be taken from point P, such that $PB - PA = λ / 4$ . Then the phase difference between the waves from A and B reaching P is

Easy

A

$156^{\circ}$
B

$140^{\circ}$
C

$136^{\circ}$
D

$126$

Solution

Total phase difference
= Initial phase difference + Phase difference due to path
$= 66^{\circ} + \frac{360^{\circ}}{λ} \times Δx = 66^{\circ} + \frac{360^{\circ}}{λ} \times \frac{λ}{4}$
$= 66^{\circ} + 90^{\circ} = 156^{\circ}$

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