Among the two interfering monochromatic sources A and B; A is ahead of B in phase by 660. If the observation be taken from point P, such that PB−PA=λ/4. Then the phase difference between the waves from A and B reaching P is
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a
156∘
b
140∘
c
136∘
d
126
answer is A.
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Detailed Solution
Total phase difference= Initial phase difference + Phase difference due to path=66∘+360∘λ×Δx=66∘+360∘λ×λ4=66∘+90∘=156∘