Among the two interfering monochromatic sources A and B; A is ahead of B in phase by 66°. If the observation be taken from point P, such that PB – PA = l/4. Then the phase difference between the waves from A and B reaching P is

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156°

140°

136°

126°

answer is A.

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Detailed Solution

Total phase difference = Initial phase difference + Phase difference due to path =66°+360°λ×Δx=66°+360°λ×λ4=66°+90=156°

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