First slide

Mass Energy equivalence

Question

The amount of energy approximately be released if all the atoms of 1kg of Deuterium could undergo fusion is (Assume in the fusion of Deuterium, 0.7% of mass is converted into energy)

Moderate

A

$8 x 10^{23} M e V$
B

$9 x 10^{13} J$
C

$1.75 x 10^{8} K w h$
D

$6 x 10^{27} C a l$

Solution

$0.7 % m a s s c o n v e r t e d i n t o e n e r g y t h e n a c c o r d i n g t o E = m c^{2} \frac{0.7 x 1 x 9 x 10^{16}}{100} J \frac{0.7 x 1 x 9 x 10^{16}}{100 x 3.6 x 10^{5}} K w h = \frac{7}{4} x 10^{8} K w h$

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