The amount of energy approximately be released if all the atoms of 1kg of Deuterium could undergo fusion is (Assume in the fusion of Deuterium, 0.7% of mass is converted into energy)

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8 x1023MeV

9 x1013 J

1.75 x 108 Kwh

6 x 1027 Cal

answer is C.

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Detailed Solution

0.7% mass converted into energy then according to E = mc2 0.7 x1 x9 x 1016100J 0.7 x1 x9 x 1016100 x3.6 x 105 Kwh=74 x 108Kwh

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