First slide

Heat given

Question

The amount of heat must be supplied to 2.0×10^–2kg of nitrogen (at room temperature) to raise its temperature by 45^oC at constant pressure is (Molecular mass of N₂ = 28;
R = 8.3J mol^–1K^–1)

Easy

A

933 J
B

1037 J
C

1868 J
D

467 J

Solution

m = 2.0 × 10^–2 kg
ΔT =45°C
N₂ is diatomic gas.
Molar mass, M = 28gm = 28 × 10–3kg, C_p = 7/2 R
R = 8.3J/mol-K
Heat supplied, Q = nC_pΔT
n = number of moles = $\frac{{2 \times {{10}^{ - 2}}}}{{28 \times {{10}^{ - 3}}}}$
$\Rightarrow n = \frac{5}{7}$
$\therefore Q = \frac{5}{7} \times \left( {\frac{7}{2} \times 8.3} \right) \times 45\,\,{\text{Joule}}$
= 933 Joule.

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App