The amount of heat must be supplied to 2.0×10–2kg of nitrogen (at room temperature) to raise its temperature by 45oC at constant pressure is (Molecular mass of N2 = 28;R = 8.3J mol–1K–1)

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933 J

1037 J

1868 J

467 J

answer is A.

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Detailed Solution

m = 2.0 × 10–2 kgΔT =45°CN2 is diatomic gas.Molar mass, M = 28gm = 28 × 10–3kg, Cp = 7/2 RR = 8.3J/mol-KHeat supplied, Q = nCpΔTn = number of moles = = 933 Joule.

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