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Q.

The amount of work done in forming a soap bubble(S.T. = 30 x 10-3 N/m) of radius 5 cm is:

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a

1.88 x 10-3J

b

1.88 x 101 J

c

1.88 X 10-1 J

d

1.88 X 103 J

answer is A.

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Detailed Solution

W=8πR2T=8×3.14×5×10-22×30×10-3=1.88×10-3J
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