The amount of work done in forming a soap film of size $10\mathrm{cm}\times 10\mathrm{cm}$ is (Surface tension $\mathrm{T}=3\times {10}^{-2}\mathrm{N}/\mathrm{m})$

• A

  $6\times {10}^{-4}\mathrm{J}$

• B

  $3\times {10}^{-4}\mathrm{J}$

• C

  $6\times {10}^{-3}\mathrm{J}$

• D

  ${\text{3×10}}^{-4}\hspace{0.17em}\mathrm{J}$