Intensity of electromagnetic wave

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Question

Amplitude of electric field in a parallel beam of light of intensity $8 w / m^{2}$ is

Moderate

Solution

$I = \frac{1}{2} ε_{0} E_{0}^{2} c \Rightarrow E_{0} = \sqrt{\frac{2 I}{ε_{0} C}} = \sqrt{\frac{2 \times 8}{8.85 \times 10^{- 12} \times 3 \times 10^{8}}} N / C = 77.62 N / C .$

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