Q.

Amplitude of electric field in a parallel beam of light of intensity 8  w/m2  is

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Detailed Solution

I=12  ε0   E02c  ⇒   E0 =  2Iε0C  =  2  ×  88.85  ×  10−12 ×  3  ×  108  N/C=77.62  N/C.
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