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The amplitude of the electric field in a parallel beam of plane electromagnetic waves of intensity $53.1 W m^{- 2}$ is (permittivity of free space= $8.85 \times 10^{- 12} C^{2} / N m^{2}$ )

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20Vm−1

200Vm−1

400Vm−1

40Vm−1

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Correct option is B

Intensity of electromagnetic wave in terms of maximum electric field isI=12∈0E02C ⇒E0=2I∈0C ⇒E0=2×53.18.85×10−12×3×108 ⇒E0=2×53.1×10426.55=4×104 ⇒E0=200Vm−1

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The amplitude of the electric field in a parallel beam of plane electromagnetic waves of intensity 53.1Wm−2 is (permittivity of free space= 8.85×10−12C2/Nm2 )

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The amplitude of the electric field in a parallel beam of plane electromagnetic waves of intensity $53.1 W m^{- 2}$ is (permittivity of free space= $8.85 \times 10^{- 12} C^{2} / N m^{2}$ )