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Questions  

The amplitude of the electric field in a parallel beam of plane electromagnetic waves of intensity106.2 Wm2 is (permittivity of free space= 8.85×1012C2/Nm2)

a
2×102Vm−1
b
22×102Vm−1
c
12×102Vm−1
d
102Vm−1

detailed solution

Correct option is B

Intensity of electromagnetic wave in terms of maximum electric field isI=12∈0E02C  ⇒E0=2I∈0C ⇒E0=2×106.28.85×10−12×3×108=22×102V/m

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