First slide

Modulation

Question

The amplitude modulated current is given by $i = 125 [1 + 0.6 \sin 2900 t] \sin 10^{6} t$ . The depth of modulation is

Easy

A

60 %
B

6 %
C

36 %
D

66 %

Solution

$C o m p a r e t h e g i v e n e q u a t i o n w i t h i = A_{c} [1 + μ \sin ω_{m} t] \sin ω_{c} t ∴ μ = 0.6 D e p t h o f m o d u l a t i o n = μ × 100 = 0.6 \times 100 = 60 %$

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