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Q.

An amplitude modulated voltage is expressed as  e=10(1+0.6cos2000πt)cos(3×106πt) volt . The minimum and maximum value of modulated carrier wave is

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a

2 V , 18 V

b

4 V , 16 V

c

2 V , 8 V

d

4 V  , 12   V

answer is B.

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Detailed Solution

Given equation is  e=10(1+0.6cos2000πt)cos(3×106πt) volt  We know that modulated wave equation is  Cm(t)=Ec(1+μCoswmt)Coswct  Comparing we get ,  Ec = 10 , μ = 0.6  Now,  Emin=(1−μ)Ec=(1−0.6)(10)=(0.4)(10)=4V Emax=(1+μ)Ec=(1+0.6)(10)=(1.6)(10)=16V
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