Questions
An amplitude modulated voltage is expressed as . The minimum and maximum value of modulated carrier wave is
detailed solution
Correct option is B
Given equation is e=10(1+0.6cos2000πt)cos(3×106πt) volt We know that modulated wave equation is Cm(t)=Ec(1+μCoswmt)Coswct Comparing we get , Ec = 10 , μ = 0.6 Now, Emin=(1−μ)Ec=(1−0.6)(10)=(0.4)(10)=4V Emax=(1+μ)Ec=(1+0.6)(10)=(1.6)(10)=16VTalk to our academic expert!
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A message signal of frequency 10 kHz and peak voltage of 10 volts is used to modulate a carrier of frequency 1 MHz and peak voltage of 20 volts. The side bands are 1010 kHz and______________kHz.
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