An amplitude modulated voltage is expressed as e=10(1+0.6cos2000πt)cos(3×106πt) volt . The minimum and maximum value of modulated carrier wave is
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a
2 V , 18 V
b
4 V , 16 V
c
2 V , 8 V
d
4 V , 12 V
answer is B.
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Detailed Solution
Given equation is e=10(1+0.6cos2000πt)cos(3×106πt) volt We know that modulated wave equation is Cm(t)=Ec(1+μCoswmt)Coswct Comparing we get , Ec = 10 , μ = 0.6 Now, Emin=(1−μ)Ec=(1−0.6)(10)=(0.4)(10)=4V Emax=(1+μ)Ec=(1+0.6)(10)=(1.6)(10)=16V