An amplitude modulated voltage is expressed as e=10(1+0.6cos2000πt)cos(3×106πt) volt . The minimum and maximum value of modulated carrier wave is

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2 V , 18 V

4 V , 16 V

2 V , 8 V

4 V , 12 V

answer is B.

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Detailed Solution

Given equation is e=10(1+0.6cos2000πt)cos(3×106πt) volt We know that modulated wave equation is Cm(t)=Ec(1+μCoswmt)Coswct Comparing we get , Ec = 10 , μ = 0.6 Now, Emin=(1−μ)Ec=(1−0.6)(10)=(0.4)(10)=4V Emax=(1+μ)Ec=(1+0.6)(10)=(1.6)(10)=16V

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