Q.
For an amplitude modulated wave, the maximum amplitude is found to be 10V while the minimum amplitude is found to be 2V. The modulation index μ is
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a
μ=3/4
b
μ=2/3
c
μ=1/3
d
μ=1
answer is B.
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Detailed Solution
since the amplitude modulated wave is given by (Ac+Amsinωmt)cosωct, the maximum amplitude is M1=Ac+Am.While the minimum amplitude is M2=Ac−Am . Hence the modulation Index isμ=AmAc=M1-M2M1 +M2=10−210+2=812=23So μ=23
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