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Q.

For an amplitude modulated wave, the maximum amplitude is found to be 10V  while the minimum amplitude is found to be  2V. The modulation index  μ is

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a

μ=3/4

b

μ=2/3

c

μ=1/3

d

μ=1

answer is B.

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Detailed Solution

since the amplitude modulated wave is given by  (Ac+Amsinωmt)cosωct, the maximum amplitude is  M1=Ac+Am.While the minimum amplitude is M2=Ac−Am . Hence the modulation Index isμ=AmAc=M1-M2M1 +M2=10−210+2=812=23So μ=23
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