An amplitude modulated wave is represented by the expression vm=51+0.4cos6280tsin211×104t volts. The minimum and maximum amplitudes of the amplitude modulated wave are, respectively

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3V,7V

3V, 5V

5V, 8V

32V,5V

answer is A.

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Detailed Solution

vm=51+0.4cos6280tsin211×104t Given : vc=5 and μ=0.4 Minimum amplitude =vc1-μ=51−0.4=3Maximum amplitude =vc1+μ=51+0.4=7No correct options

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