Questions

The amplitude of a particle executing SHM is made three-fourth keeping its time period constant. Its total energy will be

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34E

916E

None of these

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detailed solution

Correct option is C

E=12mω2a2 ⇒E'E=a'2a2 ⇒E'E=34a2a2 ∵a'=34a⇒E'=916E

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