First slide

Simple harmonic motion

Question

The amplitude of a particle executing S.H.M. with frequency of 60 Hz is 0.01 m. The maximum value of the acceleration of the particle is

Moderate

A

$144 π^{2} m / \sec^{2}$
B

$144 m / \sec^{2}$
C

$\frac{144}{π^{2}} m / \sec^{2}$
D

$288 π^{2} m / \sec^{2}$

Solution

Maximum acceleration $= {aω}^{2} = a \times 4 π^{2} n^{2}$
$= 0 .01 \times 4 \times {(π)}^{2} \times {(60)}^{2} = 144 π^{2} m / \sec^{2}$

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