Q.

The amplitude of a particle executing S.H.M. with frequency of 60 Hz is 0.01 m. The maximum value of the acceleration of the particle is

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a

144π2m/​sec2

b

144m/​sec2

c

144π2m/​sec2

d

288π2m/​sec2

answer is A.

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Detailed Solution

Maximum acceleration =aω2=a×4π2n2=0.01×4×(π)2×(60)2=144π2 m/sec2
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