The amplitude and time period of a particle of mass 0.1 kg executing simple harmonic motion are 1m and 6.28 s, respectively. Then its angular frequency and acceleration at a displacement of 0.5 m are respectively

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1 rad/s, 0.5 m/s2

2 rad/s, 1 m/s2

0.5 rad/s, 0.5 m/s2

1 rad/s , 1 m/s2

answer is A.

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Detailed Solution

ω=2πT;a=ω2x

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