The amplitude of vibration of a particle is given by am=aoaω2−bω+c, where ao, a, b & c are positive. The condition for a single resonant frequency.

see full answer

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!

An Intiative by Sri Chaitanya

b2 = 4ac

b2 > 4ac

b2 = 5ac

b2 < 4ac

answer is A.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

for single resonant frequency aw2-bw+c=0 w = +b±b2-4ac2a for single value of resonant frequency the condition is discriminant =0, b2-4ac=0 ⇒b2=4ac

Watch 3-min video & get full concept clarity