Download the app

Questions  

The amplitude of vibration of a particle is given by  am=aoaω2bω+c, where ao, a, b & c are positive. The condition for a single resonant frequency.

a
b2 = 4ac
b
b2 > 4ac
c
b2 = 5ac
d
b2 < 4ac

detailed solution

Correct option is A

for single resonant frequency aw2-bw+c=0                    w = +b±b2-4ac2a                   for single value of  resonant frequency the condition is discriminant =0,                    b2-4ac=0                   ⇒b2=4ac

Talk to our academic expert!

+91

Are you a Sri Chaitanya student?


Similar Questions

A particle of mass m is attached to a spring (of spring constant k) and has a natural angular frequency ω0 -An external force F (t) proportional to cosωt((ωω0) is applied to the oscillator. The time displacement of the oscillator will be proportional to


phone icon
whats app icon