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The amplitude of a wave represented by displacement equation y=1asinωt±1bcosωt will be

a
a+bab
b
a+bab
c
a±bab
d
a+bab

detailed solution

Correct option is D

y=1asinωt±1bsinωt+π2Here phase difference = π2  ∴The resultant amplitude =1a2+1b2=1a+1b=a+bab

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Two waves are propagating to the point P along a straight line produced by two sources A and B of simple harmonic and of equal frequency. The amplitude of every wave at P is ‘a’ and the phase of A is ahead by π3 than that of B and the distance AP is greater than BP by 50 cm. Then the resultant amplitude at the point P will be, if the wavelength is 1 meter 


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