First slide

Polarisation

Question

An analyser is inclined to a polariser at an angle of 30⁰. The intensity of light emerging from the analyser is 1/n th of that is incident on the polariser. Then n is equal to

Moderate

A

4
B

4/3
C

8/3
D

1/4

Solution

$I = \frac{{{I_0}}}{n} \Rightarrow \frac{{{I_0}}}{n} = \frac{{{I_0}}}{2}{\cos ^2}{30^0} \Rightarrow n = 8/3\$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App