The angle between two vectors A→ and B→ is 120∘, then its resultant C will be
C=|A→−B→|
C>|A→−B→|
C=-A→+B→
C<|A→−B→|
C=A2+B2+2ABcos1200=A2+B2-AB and A→-B→=A2+B2-2ABcos1200=A2+B2+AB Comparing them , we can say C<|A→−B→|