The angle between two vectors A→ and B→ is $$120$$∘, then its resultant C will be

Correct option is 4C<|A→−B→|

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The angle between two vectors $\vec{A} and \vec{B}$ $is 120^{\circ},$ then its resultant C will be

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C=|A→−B→|

C>|A→−B→|

C=-A→+B→

C<|A→−B→|

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detailed solution

Correct option is D

C=A2+B2+2ABcos1200=A2+B2-AB and A→-B→=A2+B2-2ABcos1200=A2+B2+AB Comparing them , we can say C<|A→−B→|

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The angle between two vectors A→ and B→ is 120∘, then its resultant C will be

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The angle between two vectors $\vec{A} and \vec{B}$ $is 120^{\circ},$ then its resultant C will be