The angle between two vectors given by 6i¯+6j¯−3k¯ and 7i¯+4j¯+4k¯ is
cos−1(13)
cos−1(53)
sin−1(23)
sin−1(53)
If the angle between the vectors is ‘θ ’ then
cosθ=A→.B→|A→|.|B→|
⇒cosθ=42+24−12(36+36+9)(49+16+16)
cosθ=54(9)(9)=23
∴sinθ=53
⇒θ=sin−1(53)