First slide

Vectors

Question

The angle between two vectors (i + j) and (j + k) is

Easy

A

30°
B

4s°
C

60°
D

90°

Solution

$\begin{array}{l} \cos θ = \frac{(i + j) \cdot (j + k)}{| i + j | | j + k |} = \frac{1}{\sqrt{2} \times \sqrt{2}} = \frac{1}{2} \\ θ = 60^{\circ} \end{array}$

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