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The angle between the vectors $\vec{A} and \vec{B}$ is $θ$ . The value of the triple product $\vec{A} . (\vec{B} \times \vec{A})$ is

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A2B

Zero

A2Bsinθ

A2Bcosθ

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detailed solution

Correct option is B

Let A→ .( B→ ×A→) = A→.C→Here C→ = B→ ×A→, which is perpendicular to both vectors.A→ and B→ ∴ A→.C→ = 0

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The angle between the vectors A→ and B→ is θ. The value of the triple product A→ .( B→ ×A→) is

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The angle between the vectors $\vec{A} and \vec{B}$ is $θ$ . The value of the triple product $\vec{A} . (\vec{B} \times \vec{A})$ is