Q.

The angle between the vectors A→  and  B→ is θ. The value of the triple product A→ .( B→ ×A→) is

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a

A2B

b

Zero

c

A2Bsinθ

d

A2Bcosθ

answer is B.

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Detailed Solution

Let A→ .( B→ ×A→) = A→.C→Here C→ =  B→ ×A→, which is perpendicular to both vectors.A→ and  B→    ∴ A→.C→ = 0
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The angle between the vectors A→  and  B→ is θ. The value of the triple product A→ .( B→ ×A→) is