First slide

Scalars and Vectors

Question

Angle between the vectors $(\hat{i} + \hat{j}) and (\hat{j} - \hat{k})$ is

Easy

A

90⁰
B

0⁰
C

180⁰
D

60⁰

Solution

$\cos θ = \frac{\vec{A} \cdot \vec{B}}{| \vec{A} ∥ \vec{B} |} = \frac{1}{\sqrt{2} \sqrt{2}} = \frac{1}{2} ∴ θ = 60^{\circ}$

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